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464 B
464 B
实现一个基于二分查找的整形数组查找
const indexOf_BinarySearch = (dataArr: number[], num: number): number => {
let n1 = 0;
let n2 = dataArr.length - 1;
if (n1 === num) return n1;
if (n2 === num) return n2;
while (n1 <= n2) {
const mid = Math.floor((n1 + n2) / 2);
if (num > dataArr[mid]) {
n1 = mid + 1;
} else if (num < dataArr[mid]) {
n2 = mid - 1;
} else {
return mid;
}
}
return -1;
};